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5x^2+28x-85=0
a = 5; b = 28; c = -85;
Δ = b2-4ac
Δ = 282-4·5·(-85)
Δ = 2484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2484}=\sqrt{36*69}=\sqrt{36}*\sqrt{69}=6\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-6\sqrt{69}}{2*5}=\frac{-28-6\sqrt{69}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+6\sqrt{69}}{2*5}=\frac{-28+6\sqrt{69}}{10} $
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